TASK:
Write a C-Program in which declare two int arrays, each of maximum size 100. Ask the
user to enter the size of the 1st array (maximum size can be 100), then ask the user to
enter the integer values (no duplicate value is allowed) of the 1st array. After this ask the
user to enter the size of the 2nd array (maximum size can be 100), then ask the user to
enter the integer values (no duplicate value is allowed) of the 2nd array. Assume the user
enters the correct values (no need of validation). Your code should determine and display
the UNION and INTERSECTION of these two arrays.
CODE:
#include<stdio.h>
int main(){
int m,n,temp;
printf("Enter the size of array one: ");
scanf("%d",&m);
printf("\nEnter the size of arry two: ");
scanf("%d",&n);
int arr1[m],arr2[n],i,j,c=0,un[m+n],d=0,inter[d];
//asking for entries of array one
printf("entries of Array1: \n");
for (i=0;i<m;i++)
{
printf("entry %d : ",i+1);
scanf("%d",&arr1[i]);
un[c]=arr1[i]; //using for merging
c++;
}
//asking for entries of array two
printf("Enter entries of Array2: \n");
for (i=0;i<n;i++)
{
printf("entry %d : ",i+1);
scanf("%d",&arr2[i]);
un[c]=arr2[i]; //merging continue
c++;
}
for(i=0;i<(m+n);i++)
{
int temp;
for(j=i+1; j<(m+n) ;j++)
{
if(un[i]>un[j])
{
temp=un[j];
un[j]=un[i];
un[i]=temp;
}
else if (un[i]==un[j])//storing the value for intersection
{
inter[d]=un[i];
d++;
}
}
}
//printing union
printf("\nUnion:");
printf("\n{");
for(i = 0; i < (m+n); i++){
for(j = 0; j < (m+n); j++){
if(un[i] == un[j] && i != j)
{
un[i]=54321;
break;
}
}
}
for (i=0;i<n+m;i++)
{
if (un[i]!=54321&&i!=(m+n-1))
printf("%d,",un[i]);
else if (un[i]!=54321&&i==(m+n-1))
printf("%d",un[i]);
}
printf("}");
//For intersection
printf("\nintersection: ");
printf("\n{");
for(i = 0; i < d; i++){
for(j = 0; j < (d); j++){
if(inter[i] == inter[j] && i != j)
{
inter[i]=54321;
break;
}
}
}
for (i=0;i<d;i++)
{
if (inter[i]!=54321&&i!=(d-1))
printf("%d,",inter[i]);
else if (inter[i]!=54321&&i==(d-1))
printf("%d",inter[i]);
}
printf("}");
getchar();
return 0;
}
Expected Output:
